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uranmaximum [27]
2 years ago
10

HELPPPP ASAAPPPP PLEASEEEE

Mathematics
1 answer:
lidiya [134]2 years ago
6 0

(A) n=w by the corresponding angles theorem.

(B) This is the correct answer. n=s by the vertical angles theorem and s and x are supplementary by the same-side interior angles theorem. Thus, n and x are supplementary and not always equal.

(C) n=z by the alternate exterior angles theorem.

(D) s=w, so (s+w)/2 = (s+s)/2 = s. Since n=s by the vertical angles theorem, n=s.

(E) n and w are equal by the corresponding angles theorem, and w and y are supplementary as they form a linear pair. Thus, n+y=180, and it follows n=180-y.

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9. Find mZDBC in the figure below.
ArbitrLikvidat [17]

Answer:

a. 66 degrees

Step-by-step explanation:

3 0
3 years ago
ILL GIVE BRAINLIST ON WHOEVER GETS RIGHT!!!!!!!
Korvikt [17]

Answer:

hey,its option a

Step-by-step explanation:

because angle F= angle M and angle G= angle L

and angle H= angle N

To know third angle in ∆HGF

,we know sum of all angles in a triangle is 180°

______________________________

let angle H be unknown value x

x+51+36=180

x=180-87 ---------------- 1

similarly in ∆MNL

let angle be y

51+36+y=180

y=180-87----------------2

_______________________________

From 1&2 we observe qngle x= angle y

by AAA SIMILARITY THEY ARE SIMILAR

3 0
4 years ago
Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
Write an expression for "10 multiplied by u
raketka [301]
An expression for that would be 10u
6 0
3 years ago
Read 2 more answers
73,529-9,199 = ?<br> whats the awnser?
loris [4]
64,330 is your answer. Hope this helps! :)
5 0
3 years ago
Read 2 more answers
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