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QveST [7]
3 years ago
14

I need help No links or ill report you 8!√5+6²

Mathematics
2 answers:
Soloha48 [4]3 years ago
5 0
41 or 6.4 hope this helps
soldier1979 [14.2K]3 years ago
3 0

Answer: uhh idrk bc im taking ur points ok bye <3

Step-by-step explanation:

BAHAHAHAH SORRY IDEK IF U RLLY NEED HELP OR NOT BUT YEAH IM TERRIBLE AT MATH

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Isabella is getting older and feels like she should donate her collection of stuffed animals to children who are less fortunate.
Studentka2010 [4]

Answer:

well for the cats she can do 3 for each and dogs 2 for each

3 0
3 years ago
Need help solving hi
steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

2 \ln(x+2)=6

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e^{\ln(x+2)}=e^3

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8 0
3 years ago
PLEASE HELP ASAP
Archy [21]
I feel like its either b or c
3 0
4 years ago
Read 2 more answers
A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, &amp; 30 years.
Alika [10]

Complete Question

A hypothetical population consists of eight individuals ages 13 14 17 20 21 22 24 30 years.  

A: what is the probability that a person in this population is a teenager?  

B: what is the probability of selecting a participant who is at least 20 years old?

We have that  probability that a person in this population is a teenager and probability of selecting a participant who is at least 20 years old is

From the question we are told

A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.

  • P(T)=0.38
  • P(T')=0.63

a)

Generally the equation for the  probability that a person in this population is a teenager   is mathematically given as

P(T)=\frac{no of teens}{n}\\\\P(T)=\frac{3}{8}

P(T)=0.38

b)

Generally the equation for the probability of selecting a participant who is at least 20 years old  is mathematically given as

P(T)=\frac{ participants\ who\ is\ at\ least\ 20\ years old}{n}\\\\P(T)=\frac{5}{8}

P(T')=0.63

For more information on this visit

brainly.com/question/11234923?referrer=searchResults

6 0
2 years ago
If two rays are opposite rays, then they have a common endpoint.​
Ilia_Sergeevich [38]

The statement is true.

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3 years ago
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