Answer:
The percentage is k
%
Explanation:
From the question we are told that
The mass of the stibnite is 
The volume of KBrO3(aq) is 
The concentration of KBrO3(aq) is 
Now the balanced ionic equation for this reaction is

The number of moles of
is

substituting values


from the reaction we see that 1 mole of
reacts with 3 moles of 
so 0.003325 moles will react with x moles of 
Therefore


Now the molar mass of
is a constant with a values of 
Generally the mass of
is mathematically represented as

substituting values

The percentage of Sb(antimony) in the overall mass of the stibnite is mathematically evaluated as
k 
k
%
Answer:
The mass of 3.5 moles of Ca is 140 g to two significant figures.
Explanation:
For the triplet AUG, I got methionine, which is a start codon. For GCU, I got alanine.
Answer:
0.7 moles of Chlorine gas is required.
Explanation:
The reaction is balanced as follows:
2Na +
------> 2NaCl
According to stoichiometry,
2 mole Sodium reacts with 1 mole Chlorine gas
∴1 mole Sodium reacts with 1/2 moles of Chlorine gas
∴1.4 mole sodium reacts with 1.4/2 moles of Chlorine gas
= 0.7 moles of Chlorine gas
So, 0.7 moles of Chlorine gas is required.