Cross aldol condensation reaction was carried out by reacting Acetone with Benzaldehyde in presence of sodium hydroxide. How man
y alpha carbon are present in acetone
1 answer:
Answer:
Carbons 1 and 3
Explanation:
We must remember that by definition <u>alpha carbon</u>s are the carbon (or carbons) next to the carbon that contains the main group. In this case, the main group is the carbonyl group (C = O) in the middle of the molecule. In the acetone molecule, we have three carbons, the carbons neighboring the carbon of the carbonyl group (carbon two) will be the <u>alpha carbons</u>. (Red and blue carbons or carbons one and three)
See figure 1 for further explanations.
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Answer:
0.3023 M
Explanation:
Let Picric acid =
So, +
⇄
+
The ICE table can be given as:
+
⇄
+
Initial: 0.52 0 0
Change: - x + x + x
Equilibrium: 0.52 - x + x + x
Given that;
acid dissociation constant () = 0.42
0.42(0.52-x) = x²
0.2184 - 0.42x = x²
x² + 0.42x - 0.2184 = 0 -------------------- (quadratic equation)
Using the quadratic formula;
; ( where +/- represent ± )
=
=
= OR
= OR
= OR
= 0.30225 OR - 0.72225
So, we go by the +ve integer that says:
x = 0.30225
x = [ ] = [
] = 0.3023 M
∴ the value of [H3O+] for an 0.52 M solution of picric acid = 0.3023 M (to 4 decimal places).
Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 0.947 atm
= final pressure of gas = 0.987 atm
= initial volume of gas = 150 ml
= final volume of gas = 144 ml
= initial temperature of gas =
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is