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2 years ago

Use the table to the right to answer the following question.

Mathematics

1 answer:

Paladinen [302]2 years ago

8 0

Fission of 1 kg of element B releases 2941 times as much energy as burning 1 kg of element A

<h3>How to compare the energy released?</h3>

The given parameters are:

Energy A = 5.1 * 10^7

Energy B = 1.5 * 10^11

The amount of energy B in proportion to energy A is calculated as

Proportion = Energy B/Energy A

So, we have:

Proportion = (1.5 * 10^11)/(5.1 * 10^7)

Divide 1.5 by 5.1

Proportion = 0.2941 * 10^11/10^7

Divide 10^11 by 10^7

Proportion = 0.2941 * 10^4

Evaluate

Proportion = 2941

Hence, fission of 1 kg of element B releases 2941 times as much energy as burning 1 kg of element A

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