Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy =
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) = 
- 
⇒ x + iy = 
⇒ x + iy = 
[ ∵ 
]
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
Answer:
7) (f+g)(x) = 4^x +5x -5
8) (f-g)(x) = 4^x +x +5
Step-by-step explanation:
7) add the two expressions.
(f+g)(x) = f(x) +g(x) = (4^x +3x) +(2x -5)
(f+g)(x) = 4^x +5x -5
__
8) subtract g(x) from f(x).
(f-g)(x) = f(x) -g(x) = (4^x +3x) -(2x -5) = 4^x +3x -2x +5
(f-g)(x) = 4^x +x +5
Im sure this means add because on a number line when you move to the right its adding. And since the amount of units were moving up by is 6 we would add 0+6 which equals 6.
Answer:
Chesa will make 4 gallons of soup this year.
Step-by-step explanation:
If you multiply 32 times 2 you will get 64. You then find out how many cups are in a gallon. If 16 cups are in a gallon, you then divide 64 by 16. Your answer should be 4.
Y could equal anything equal to or greater than 3. you can use 3, 4, 5, 6, 7 etc.
