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3 years ago

How much is 5.802 less than 74.14

Mathematics

1 answer:

Wewaii [24]3 years ago

4 0

Answer:

68.338

Step-by-step explanation:

to know how much is less than we have to substract

74.14-5.802=68.338

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Equivalent problem please help

Airida [17]

What’s the problem doggggggggggg

8 0

3 years ago

Write the equation of the line shown in point-slope form. (2,1) (3,8)

Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

$\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}$

${(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)$ ..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

$(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)$

$(y -8) = \frac{(- 7)}{(-1)}(x-3)$

y – 8 = 7(x – 3)

y – 8 = 7x – 21

7x – y = 21 – 8

7x – y = 13

Hence, the line equation that passes through the given points is 7x – y = 13

3 0

3 years ago

Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a

Vikki [24]

Answer:

$0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730$

$0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890$

And the confidence interval would be:

$0.730 \leq \p \leq 0.890$

Step-by-step explanation:

Information given:

$n=131$ represent the sample size

$\hat p=0.81$ represent the estimated proportion

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.326$

And replacing into the confidence interval formula we got:

$0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730$

$0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890$

And the confidence interval would be:

$0.730 \leq \p \leq 0.890$

6 0

3 years ago

What is the reciprocal of 3/7. Type your final answer only with no spaces and using the backslash to separate the numerator and

Gennadij [26K]

Answer:

7/3

Step-by-step explanation:

Used a calculator

4 0

3 years ago

Read 2 more answers

Ryan is looking for the sum of the cube of a number, n, and 16.

Paraphin [41]

Answer:

Step-by-step explanation:

Changing the word problem into an equation you get that you are trying to find n^3+16. This is because they are looking for the cube of a number n plus 16. Plugging in n as 2 you get 2^3+16 which is 8+16 which is 24.

7 0

3 years ago

How much is 5.802 less than 74.14​

How much is 5.802 less than 74.14