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Sindrei [870]
3 years ago
6

6 3/10 divided by 9/5

Mathematics
2 answers:
ankoles [38]3 years ago
6 0
60/3 ÷ 9/5
60/3 × 5/9
300/27
= 100/9
= 11 \frac{1}{9}
hram777 [196]3 years ago
5 0
6\frac{3}{10} ÷ \frac{9}{5} → First step is to make all the fractions improper.

\frac{63}{10} ÷ \frac{9}{5} → Now you want to flip the second fraction and multiply.

\frac{63}{10} * \frac{5}{9} → Multiply the fractions by multiplying the top numbers and then the bottom numbers. There is a simple trick I will explain later.

\frac{315}{90} → Reduce this fraction to lowest terms (The largest factor in both is 45, so divide each side by 45)

\frac{7}{2} → In decimals this is 3.5, in mixed fractions this is 3\frac{1}{2}, and in percent this is 350%.

The little trick is you can <span>cancel out numbers with common factors on the diagonals during the multiplication of fractions.

</span>\frac{63}{10} * \frac{5}{9}

The 63 and 9 are on diagonals. They both have a common factor of 9, so divide both numbers by 9. Now the fractions looks like:

\frac{7}{10} * \frac{5}{1}

The 10 and 5 are on diagonals. They both have a common factor of 5, so divide both numbers by 5. Now the multiplication looks like:

\frac{7}{2} * \frac{1}{1} → easily multiplies to \frac{7}{2}

Look how simple that was? The multiplication is already reduced into lowest terms. All you need to do is divide common factors.
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The mean weight 20 students in a room is 65 kg one student one student who weight is 88kg went into the room what is the new mea
umka2103 [35]

The new mean is 66.09

<u>Explanation:</u>

Mean weight of 20 students = 65kg

One student with 88kg entered the room.

New mean = ?

\frac{x_1+x_2+....+x_2_0}{20} = 65

\frac{x_1+x_2+....+x_2_0 + 88}{21} = ?

The above equation can further be written as:

x_1 + x_2 +....+x_2_0 = 65 X 20\\\\x_1 + x_2 +....+x_2_0 = 1300

New mean = \frac{1300 + 88}{21}

                 = 66.09

Therefore, the new mean is 66.09

6 0
3 years ago
HELP PLS<br> BRAINLEIST<br> 10 POINTS
qwelly [4]

Answer:

26 is the answers for the question

4 0
2 years ago
The sides of △FGH are FG = 6 x+ 7, GH = 8x - 5, and FH = 10x - 11. If the perimeter of △FGH is 87, list the angles in order from
irga5000 [103]

Answer:

From largest to smallest: FG, FH, GH

Step-by-step explanation:

Given

FG = 6x + 7

GH = 8x - 5

FH = 10x - 11

Perimeter = 87

Required

Order the sides in descending order

First, we need to solve for x.

Perimeter of FGH is calculated as thus:

Perimeter = FG + GH + FH

Substitute values for FG, GH, FH and Perimeter

87 = 6x + 7 + 8x - 5 + 10x - 11

Collect Like Terms

87 - 7 + 5 + 11= 6x + 8x + 10x

96= 24x

Reorder

24x = 96

Divide through by 24

x = 96/24

x = 4

Substitute 4 for x in FG, GH and FH

FG = 6x + 7

FG = 6 * 4 + 7

FG = 24 + 7

FG =31

GH = 8x - 5

GH = 8 * 4 - 5

GH = 32 - 5

GH = 27

FH = 10x - 11

FH = 10*4 - 11

FH = 40 - 11

FH = 29

In order of arrangement in descending order, we have:

FG =31    FH = 29     GH = 27

4 0
2 years ago
Use the Law of Sines to find each missing side or angle. Round to the nearest tenth.
Gre4nikov [31]
(22 x sin(65))/sin(53) =24.96604654 rounded of to nearest tenth = 25
So X = 25
5 0
1 year ago
Select the correct answer.
maksim [4K]

Answer: B

Step-by-step explanation:

5 0
2 years ago
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