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2 years ago

Writing an Equation from a Table

Mathematics

1 answer:

Anastasy [175]2 years ago

7 0

The equation of the line will be y = 4x. Then the correct option is A.

<h3>What is the equation of line?</h3>

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

Writing an Equation from a Table

A 2-column table with 6 rows. Column 1 is labeled x with entries 8, 12, 16, 20, 24, 28. Column 2 is labeled y with entries 2, 3, 4, 5, 6, 7.

Then at (2, 8) and (3, 12), we have

y – 8 = [(12 – 8) / (3 – 2)] (x – 2)

y – 8 = 4x – 8

y = 4x

Then the correct option is A.

More about the equation of line link is given below.

brainly.com/question/21511618

#SPJ1

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Item 15 Question 1 Show that quadrilateral WXYZ with vertices W(−1,6), X(2, 8), Y(1, 0), and Z(−2,−2) is a parallelogram by find

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Multiple answers

Step-by-step explanation:

A parallelogram is a flat shape that has four sides. The two sets of opposite sides are parallel and of equal length to each other.

To prove that our figure is a parallelogram we first get the slope of our sides.

The formule we use to get the slope is:

m = $\frac{y-y1}{x-x1}$

first we have the W-Z side that it's supossed to be parallel to X-Y side

if we use our formule to calculate the slope of W-Z:

$\frac{6-(-2)}{-1-(-2)}$ = $\frac{8}{1}$ = 8

if we use our formule to calculate the slope of X-Y:

$\frac{8-0}{2-1}$ = $\frac{8}{1}$ = 8

We know that parallel lines will never intersect because they have the same slope, therefore W-Z side is parallel to X-Y side

2. Then we have the W-X side that it's supossed to be parallel to Z-Y side

if we use our formule to calculate the slope of W-X:

$\frac{6-8}{-1-2}$ = $\frac{-2}{-3}$

if we use our formule to calculate the slope of Z-Y:

$\frac{-2-0}{-2-1}$ = $\frac{-2}{-3}$

We know that parallel lines will never intersect because they have the same slope, therefore W-X side is parallel to Z-Y side

Then we have to prove that the parallalel sides are equal length to each other.

The formule we use to get the distance between two points is:

$\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }$

We calculate the lenght of the W-Z side that it's supossed to be equal to X-Y side:

W-Z = $\sqrt{(-1-(-2))^{2}+(6-(-2))^{2} }$ = $\sqrt{65}$

X-Y = $\sqrt{(2-1)^{2}+(8-0)^{2} }$ = $\sqrt{65}$

So the W-Z side have the same lenght to X-Y side.

We calculate the lenght of the W-X side that it's supossed to be equal to Z-Y side:

W-X = $\sqrt{(-1-2)^{2}+(6-8)^{2} }$ = $\sqrt{13}$

Z-Y = $\sqrt{(-2-1)^{2}+(-2-0)^{2} }$ = $\sqrt{13}$

So the W-X side have the same lenght to Z-Y side.

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