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Tresset [83]
2 years ago
11

Given f(x) = 4x + 1 and g(x) = x^, choose the expression for (fᵒg)(x).

Mathematics
2 answers:
Galina-37 [17]2 years ago
4 0

Answer: 4x^2 + 1

Step-by-step explanation:

I am assuming g(x) = x^2

4(x^2) + 1

4x^2 + 1

frutty [35]2 years ago
3 0

Answer:

(fog)(x)=4x^2+1

Step-by-step explanation:

Assume g(x)=x^2

(fog)(x) is a composition of two functions such that (fog)(x)=f(g(x)).

Consider the function:

f(x)=4x+1

Replace x with g(x) into the equation:

f(g(x))=4\cdot g(x)+1

Substitute g(x)=x^2 on the right side of the equation:

f(g(x))=4\cdot x^2+1

Therefore, the expression for (fog)(x) is 4x^2+1.

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Consider the differential equationy′′+3y′−10y=0.(a) Find the general solution to this differential equation.(b) Now solve the in
RSB [31]

Answer:

Y= 2e^(5t)

Step-by-step explanation:

Taking Laplace of the given differential equation:

s^2+3s-10=0

s^2+5s-2s-10=0

s(s+5)-2(s+5) =0

(s-2) (s+5) =0

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Hence, the general solution will be:

Y=Ae^(-2t)+ Be^(5t)………………………………(D)

Put t = 0 in equation (D)

Y (0) =A+B

2 =A+B……………………………………… (i)

Now take derivative of (D) with respect to "t", we get:

Y=-2Ae^(-2t)+5Be^(5t)   ....................... (E)

Put t = 0 in equation (E) we get:

Y’ (0) = -2A+5B

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2(i) + (ii) =>

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By putting the values of A and B in equation (D)

Y= 2e^(5t)

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