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marusya05 [52]
2 years ago
6

#10 Compare the numbers below using <, > or = -67 _-62

Mathematics
2 answers:
larisa [96]2 years ago
4 0

Answer: the answer is -67<-62

Step-by-step explanation:

NNADVOKAT [17]2 years ago
4 0

Answer:

-67<-62

Step-by-step explanation:

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y-intercept: (0, 3)

Step-by-step explanation:

Attached is a screenshot of the plotted points (-1, 1) and (1, 5) on a graph. It shows that the line crosses the y-axis at point (0, 3) → which is the y-intercept.

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124 ounces decreased by 67%
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40.92 ounces.
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The aspect ratio of a TV screen is a ratio of the screen's width to the screen's height. Suppose that Noel recycles an old TV sc
Paul [167]

If the diagonal is 32 than you will us

A^2 + b^2 = c^2

We will use the aspect ratio to find a common variable

4A = 3B

a = (3/4)B now plug it in

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8 0
2 years ago
300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
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