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2 years ago

#10 Compare the numbers below using <, > or = -67 _-62

Mathematics

2 answers:

larisa [96]2 years ago

4 0

Answer: the answer is -67<-62

Step-by-step explanation:

NNADVOKAT [17]2 years ago

4 0

Answer:

-67<-62

Step-by-step explanation:

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(−4x^4 +6x^2 +3) − (5x^2 - 3)

Alborosie

Answer:

$-4x^{4} + x^{2} + 6$

Step-by-step explanation:

$(-4x^{4} + 6x^{2} + 3) - (5x^{2} - 3) = -4x^{4} + 6x^{2} + 3 - 5x^{2} + 3 = -4x^{4} + 6x^{2} - 5x^{2} + 3 + 3 = -4x^{4} + x^{2} + 6$

7 0

3 years ago

in a 3-digit number, the hunderds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s

Stels [109]

Answer:362

Step-by-step explanation:

So, the ones digit is 2. Since the hundreds digit is one more, it's 3. And because the tens is twice the hundreds, it's 6. The number is 362

5 0

3 years ago

Monthly payment of 1,000 where interest is 6% compounded monthly

inessss [21]

Answer: you would have 1,060 in a month if that’s what you are asking

Step-by-step explanation:

6 0

3 years ago

What is the product? 8(–1) A. –1.4 B. –8 C. 8 D. 11.2

enot [183]

B: -8
8 times 1 = 8, and since there is a negative in front of the 1 when you are multiplying, it should be -8/

7 0

3 years ago

Read 2 more answers

Statements that are true for a cylinder with radius r and height h.

vampirchik [111]

Answer:

Only the second and third statements are correct:

Doubling r quadruples the volume.

Doubling h doubles the volume.

Step-by-step explanation:

The volume of a cylinder is given by:

$\displaystyle V=\pi r^2h$

We can go through each statement and examine its validity.

Statement 1)

If the radius is doubled, our new radius is now 2r. Hence, our volume is:

$\displaystyle V=\pi (2r)^2h=4\pi r^2h$

So, compared to the old volume, the new volume is quadrupled the original volume.

Statement 1 is not correct.

Statement 2)

Using the previous reasonsing, Statement 2 is correct.

Statement 3)

If the height is doubled, our new height is now 2h. Hence, our volume is:

$V=\pi r^2(2h)=2\pi r^2h$

So, compared to the old volume, the new volume has been doubled.

Statement 3 is correct.

Statement 4)

Statement 4 is not correct using the previous reasonsing.

Statement 5)

Doubling the radius results in 2r and doubling the height results in 2h. Hence, the new volume is:

$V=\pi (2r)^2(2h)=\pi (4r^2)(2h)=8\pi r^2h$

So, compared to the old volume, the new volume is increased by eight-fold.

Statement 5 is not correct.

7 0

3 years ago