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Maru [420]
2 years ago
11

HI! PLEASE HELP!! I just need the postulate or theorem, i know how to do the problem! (:

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
4 0
Corresponding Angles Theorem
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Is the given point interior, exterior, or on the circle (x + 2)2 + (y - 3)2 = 81? P(8, 4)
Elodia [21]
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.

So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...

d^2=(8--2)^2+(4-3)^2  and d^2=r^2=81 so

81=10^2+1^2

81=101  which is not true...

So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.  

Thus the point lies outside or on the exterior of the circle...
8 0
2 years ago
6. The diagram on the right shows the cross-section of a cylindrical pipe with water lying in the bottom. a) If the maximum dept
riadik2000 [5.3K]

Answer:

404 cm³ Anyway... Look down here for my explanation.

Step-by-step explanation:

Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.

We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)

44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°

The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.

Shaded area 88.8/360*area of circle - ½*7*788.8°

= 88.8/360*π*7² - 24.5*sin 88.8°

13.5 cm²

(using area of ∆ = ½.a.b.sin C for the triangle)

Volume of water = cross-sectional area * length

13.5 * 30 cm³

404 cm³

6 0
1 year ago
What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?
AlladinOne [14]

Answer:

  -1

Step-by-step explanation:

See the attachment for the polynomial long division. The constant in the quotient is -1.

_____

Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.

That could be a first guess in a "guess and check" solution approach.

<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).

<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2

Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.

6 0
3 years ago
HELP :Write the expression as the<br> sine or cosine of an angle.
Reptile [31]

Answer:

sin(4π/21)

Step-by-step explanation:

Step 1: Rearrange expression

sin(π/3)cos(π/7) - cos(π/3)sin(π/7)

Step 2: Use sin(A ± B)

sin(π/3 - π/7)

Step 3: Evaluate

sin(4π/21)

And we have our answer!

5 0
3 years ago
Is the answer for Carla the baker 76 cookies baked per hour?
Naddika [18.5K]
5 hours         380 cookies
---------    =  -----------------
    5                       5


380/5 = 76 cookies made each hour
3 0
3 years ago
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