Use the FOLD method<span>
(a+b)(c+d)=ac+ad+bc+bd
</span><span>−12<span>s<span><span>^2 </span><span></span></span></span>+ 3st + 8ts − 2<span>t<span><span>^2</span><span>
</span></span></span></span>Collect like terms
-12{s}^{2}+(3st+8st)-2{t}^{2}
Simplify
<span>-12{s}^{2}+11st-2{t}^{2}<span>−12<span>s<span><span>2</span><span></span></span></span>+11st−2<span>t<span><span>2
The answer is = -12s^2 + 11st - 2t^2</span></span></span></span></span>
Find the area of the square first
Area = Length x Width
Area = 12 x 9
Area = 108
Find the area of the right triangles
Area = 1/2(Length x Base)
Area = 1/2(9 x 2)
Area = 1/2(18)
Area = 9
Since there is 2 triangles multiply by 2
9 x 2 = 18
Now add
108 + 18 = 126
126 is your area
Answer:
2. 3/4 x 5/9 = 3x5/4x9 = 15/36 = 5/12
4. 4/7 x 1/2 = 4x1/7x2 = 4/14 = 2/7
6. 4/9 x 2/3 = 4x2/9x3=8/27
Step-by-step explanation:
Hope it helps!
I used 3.14 for pi to solve easier.
6. 6.28
7. 21.98
8. 94.2
