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Aloiza [94]
2 years ago
13

Abcd is a trapizium calculate the area of the area of abcd 10 9 7 15

Mathematics
1 answer:
Georgia [21]2 years ago
5 0

The area of the trapezoid is 87.5 square cm if the parallel side lengths are 10 and 15 cm, the height is 7 cm.

<h3>What is a trapezoid?</h3>

It is defined as the quadrilateral having four sides in which two sides are parallel to each other, it is a 2-dimensional geometry.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have a trapezoid ABCD shown in the picture.

As we know the area of the trapezoid is given by:

= (a+b)h/2

= (10+15)(7/2)

= 87.5 square cm

Thus, the area of the trapezoid is 87.5 square cm if the parallel side lengths are 10 and 15 cm, the height is 7 cm.

Learn more about the trapezoid here:

brainly.com/question/8643562

#SPJ1

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Delicious77 [7]

QUESTION 1

4 {p}^{2}  =  2 \times 2\times  {p} \times p

QUESTION 2

39 {b}^{3}  {c}^{2}  = 3 \times 13 \times  {b} \times b \times b\times  {c} \times c

QUESTION 3

100 {x}^{3} y {z}^{2}  =  {2} \times 2 \times  {5} \times 5  \times  {x} \times x \times x\times y \times  {z} \times z

QUESTION 4

66 {d}^{4}  = 2 \times 3 \times 11 \times  {d} \times d \times d \times d

QUESTION 5

85 {x}^{2}  {y}^{2}  = 5 \times 17 \times  {x} \times x   \times {y} \times y

QUESTION 6

18xy = 2 \times  {3}^{2}  \times x \times y

36 {y}^{2}  =  {2}^{2} \times  {3}^{2}   \times  {y}^{2}

The greatest common factor is the product of the least powers of the common factors;

GCF=2 \times  {3}^{2}  \times y

GCF=18y

QUESTION 7

25mn =  {5}^{2}  \times m \times n

21m = 3 \times 7 \times m

GCF=m

QUESTION 8

15a = 3 \times 5 \times a

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GCF=a

QUESTION 9

24 {d}^{2}  =  {2}^{3}  \times 3 \times  {d}^{2}

30 {c}^{2} d = 2 \times 3 \times 5 \times d

GCF=2 \times 3 \times d

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QUESTION 10

20gh =  {2}^{2}  \times 5 \times g \times h

36 {g}^{2}  {h}^{2}  =  {2}^{2}  \times  {3}^{2}  \times  {g}^{2}  \times  {h}^{2}

GCF= {2}^{2}  \times g \times h

GCF=4gh

QUESTION 11

17 {c}^{3}  {d}^{2}  = 17 \times  {c}^{3}  \times  {d}^{2}

5 {c}^{2}  {d}^{2}  = 5 \times  {c}^{2}  \times  {d}^{2}

GCF= {c}^{2}  \times  {d}^{2}

GCF= {c}^{2}{d}^{2}

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