Ask question

Ask question

All categories

3 years ago

13

Please help! 15 points to whoever graphs and solves it!

1 answer:

monitta3 years ago

4 0

First you have to get the equation into slope/intercept format: y = mx + b

$3y > -3+6x\\\\\frac{3y}{3} >\frac{-3+6x}{3} \\y >\frac{3(-1+2x)}{3} \\y > -1+2x\\\\y>2x-1$

So the slope m = 2, and the y-intercept b = -1.

b tells you where the line intersects the y axis. The slope is rise (vertical distance) over run (horizontal distance). I have attached my best attempt at drawing this without graph paper. The dotted line represents the inequality, and the solution set includes the values above the line which is why it is shaded. Hope this helps!

You might be interested in

Find the length of each arc. Use the exact answer

Cerrena [4.2K]

Answer:

Option D = 16π/3 ft

Step-by-step explanation:

Arc length formula is written Mathematically as:

Arc length = 2πr × θ /360

r = 4 ft

θ = Central angle in degrees = 240°

2 × π × 4 × 240/360

8π × 240/360

8π × 20/30

16π/3 ft

So, the arc length is 16π/3 ft

3 0

2 years ago

The length of one side of a regular pentagon is 18.3 cm. What is the perimeter of this pentagon?

Ket [755]

91.5 is the perimeter. It's just 5a.

3 0

3 years ago

You wash dishes for a chemistry laboratory to make extra money for laundry. You earn 12 dollars/ hour, and each shift lasts 75 m

melomori [17]

It would pay with 3 loads

8 0

3 years ago

Read 2 more answers

What is the x-intercept of 5y=10-4x

Advocard [28]

The x intercept is 2.5

5 0

3 years ago

Read 2 more answers

For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in

Rainbow [258]

Answer:

$\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

x₁ - 5x₂ + x₄ = 5

Matrix form

$\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}$ $\begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}$

Generally the echelon reduction is mathematically applied as

$\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}$

Add -2 times the 1st row to the 2nd row

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}$

Multiply the 2nd row by -1/8

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}$

Add -1 times the 2nd row to the 3rd row

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}$

Multiply the 3rd row by -8/41

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

$\begin{Vmatrix}1 & 3 & 0&49/41&165/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

Add -3 times the 2nd row to the 1st row

$\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

3 0

2 years ago