Question

Please help!!!!!!!!!!!

Answer 1

Let's take this problem step by step:

To find the ordered pair of the system:

⇒ must set both equations equal to each other

    ⇒ and solve for 'x'

Let's solve:

 $x^2-2x+3=-2x+19\\x^2-2x+2x+3-19=0\\x^2-16=0\\(x+4)(x-4)=0$

Let's find the x-values:

   $(x-4)=0\\x=4\\\\(x+4)=0\\x=-4$

Let's find f(x)'s value for each 'x':

 $x=4\\f(4)=-2(4)+19=-8+19=11\\\\x=-4\\f(-4)=-2(-4)+19=8+19=27$

Answer: (4, 11), (-4,27)

Hope that helps!

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