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yarga [219]
2 years ago
12

Given the function f(x) below, evaluate 3f(-2) + f(1).

Mathematics
1 answer:
Ray Of Light [21]2 years ago
5 0

Answer: 45

Step-by-step explanation: I used a graphing calculator and input all the equations and all the restraints, and I found that you can’t use the first equation since x has to be less than or equal to -3, and the question calls for x to be -2. So, in the second equation, there’s a point (-2, 16) and in the third equation there’s a point (1, -3). You know you have to use these two points since in the second equation, the restraint only lets you use numbers greater than -3 or less than 0, which cannot be one, and in the third equation, the restraint only lets you use numbers greater than 0, which can’t be -2. I hope that made some sense. So then, with substitution the equation would be 3(16)+(-3) which equals 45. 3(16)=48. 48-3+=45

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The interior angles of a quadrilateral are 2x+15 2x-5 3x+75 3x-25 find x and the smallest interior angle largest interior angle
BartSMP [9]

Answer:x=30^{\circ}

Step-by-step explanation:

We know sum of the interior angles of a quadrilateral is 360^{\circ}

therefore  we can write

(2x+15)+(2x-5)+(3x+75)+(3x-25)=360^{\circ}

so

\Rightarrow 10x+60=360

\Rightarrow 10x=300

\Rightarrow x=30^{\circ}

So smallest interior angle is (2x-5)^{\circ}=(60-5)=55^{\circ}

Largest interior angle =3x+75=90+75=165^{\circ}

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3 years ago
Nathan wants to use coordinate geometry to prove that the opposite sides of a rectangle are congruent. He places parallelogram A
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We can write the formula as
CD = \sqrt{( x_{1}- x_{0})  ^{2}+ ( y_{1}- y_{0})  ^{2}  }
CD = \sqrt{(a-0)^{2}+ (b-b)^{2}  }

7 0
4 years ago
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The perimeter of the figure below is 141.8ft. Find the length of the missing side
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Step-by-step explanation:

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Which system of equations has only one solution? 4 x + 2 y = 8. Negative 4 x minus 2 y = 3. Negative 5 x + y = 6. 5 x minus y =
madam [21]

Answer:

Following system of equations have exactly one solution:

2 x + 4 y = 6\\ 3 x - 4 y = 9

Step-by-step explanation:

Given 4 system of equations:

1st  

4 x + 2 y = 8\\ -4 x -2 y = 3

2nd

-5 x + y = 6\\ 5 x - y = - 6

3rd

- 3 x + 4 y = 2\\ 3 x - 4 y = 0

4th

2 x + 4 y = 6\\ 3 x - 4 y = 9

To find: Which system of equations has only one solution?

Solution:

First of all, let us learn the concept.

Let the equation of lines be:

a_1x+b_1y+ c_1=0 and  a_2x+b_2y+ c_2=0

1. No solution:

There exists no solution if:

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq\dfrac{c_1}{c_2}

2. Infinite solutions:

There exist infinitely many solutions if:

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

3. One solution:

There exists one solution if:

\dfrac{a_1}{a_2}\neq\dfrac{b_1}{b_2}

Now, let us consider the given equations one by one.

1st system of equations:

The ratio is:

\dfrac{4}{-4} , \dfrac{2}{-2} , \dfrac{8}{3}\\-1 =-1\neq \dfrac{8}{3}

So, no solution.

2nd system of equations:

The ratio:

\dfrac{-5}{5} , \dfrac{-1}{1} , \dfrac{6}{-6}\\-1 =-1=-1

So, infinitely many solutions.

3rd system of equations:

\dfrac{3}{-3} , \dfrac{-4}{4} , \dfrac{0}{2}\\-1 =-1\ne0

So, no solution.

4th system of equations:

\dfrac{2}{3} , \dfrac{4}{-4} , \dfrac{6}{9}\\\dfrac{2}{3} \ne-1

Hence, <em>only one solution.</em>

<em></em>

<em>So, the answer is:</em>

Following system of equations have only one solution:

2 x + 4 y = 6\\ 3 x - 4 y = 9

8 0
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