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castortr0y [4]
2 years ago
6

During 1964, in a certain country, the average number of children eating lunches at school each day was 29336 which represents 7

4% of the total number of children attending school. Calculate the total number of children attending school in that country?
Mathematics
1 answer:
Rudik [331]2 years ago
8 0

Answer:

<em>The total number of children attending school was 39643</em>

Step-by-step explanation:

<u>Percentages</u>

To calculate the percentage of a quantity X with respect to another quantity Y, we use the formula:

\displaystyle P=\frac{X }{Y}*100

Where Y is the base or reference quantity. If we already know the percentage, but not the base quantity Y, we reverse the formula:

\displaystyle Y=\frac{X }{P}*100

During 1964 the number of children eating lunches at school was 29336 per day. We know that quantity is 74% of the total number of children attending school.

We use the above formula to find the base quantity:

\displaystyle Y=\frac{29336 }{74}*100

Y\approx 39643

The result was rounded to the closest integer.

The total number of children attending school was 39643

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Answer:

-0.03

Step-by-step explanation:

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x=1.8/-59

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3 0
2 years ago
The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand
alexira [117]

Answer:

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }  

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Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given Mean of the Population (μ) = 8.0

<em>Mean of the sample (x⁻) = 8.25</em>

Given data

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Given sample size  n= 8

Given sample standard deviation(S) = 0.661

<u><em>Step(ii):-</em></u>

<em>Null hypothesis : H:  (μ) = 8.0</em>

<em>Alternative Hypothesis :H:(μ) > 8.0</em>

<em>Degrees of freedom = n-1 = 8-1=7</em>

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }<em></em>

<em>              </em>t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }<em></em>

<em>            t =  1.076</em>

<em>Critical value </em>

<em>                    t₍₇,₀.₀₅₎   = 2.3646</em>

<em>The calculated value   t =  1.076 < 2.3646 at 0.05 level of significance</em>

<em>Null hypothesis is accepted</em>

<em>Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0</em>

<em></em>

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3 years ago
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Answer:

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Step-by-step explanation:

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A≈50.27

area of the square:

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64 - 50.27

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7 0
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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