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vovikov84 [41]
2 years ago
7

F(x)=(5x+3)(x−2)(3x+7)(x+5) has zeros at x = -5, x = -7/3, x = 2

Mathematics
1 answer:
musickatia [10]2 years ago
5 0

The sign of f on the interval -7/3 < x < -3/5 is always positive.

<h3>How to solve for the sign on the interval</h3>

We have the equation

(5x+3)(x−2)(3x+7)(x+5) > 0

Now when f(x) > 0

Then -7/3 < x < -3/5

This would tell us that the sign would become positive when it changes from the less than to greater than sign

<h3>Complete Question</h3>

f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2

What is the sign of f on the interval -7/3<x<-3/5?

answer choices

f is always positive on the interval

f is always negative on the interval

f is sometimes positive and sometimes negative on the interval

f is never positive or negative on the interval

Read more on polynomials here:

brainly.com/question/2833285

#SPJ1

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Step-by-step explanation:

Solution:-

- The given equation is as follows:

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Factor Approach:

- Using the constant "7" at the end of the quadratic equation we will determine two integer multiples such that their additions/subtraction results in "-8".

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- So the solution to the quadratic equation is:

                        x = 1 , 7

               

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3 years ago
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