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vovikov84 [41]
2 years ago
7

F(x)=(5x+3)(x−2)(3x+7)(x+5) has zeros at x = -5, x = -7/3, x = 2

Mathematics
1 answer:
musickatia [10]2 years ago
5 0

The sign of f on the interval -7/3 < x < -3/5 is always positive.

<h3>How to solve for the sign on the interval</h3>

We have the equation

(5x+3)(x−2)(3x+7)(x+5) > 0

Now when f(x) > 0

Then -7/3 < x < -3/5

This would tell us that the sign would become positive when it changes from the less than to greater than sign

<h3>Complete Question</h3>

f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2

What is the sign of f on the interval -7/3<x<-3/5?

answer choices

f is always positive on the interval

f is always negative on the interval

f is sometimes positive and sometimes negative on the interval

f is never positive or negative on the interval

Read more on polynomials here:

brainly.com/question/2833285

#SPJ1

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egoroff_w [7]
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2. A bag contains 25 paise coins and 50 paise Coins. The number of 25 paise coins is 6 times that of so paise Coins The total va
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<h2>~<u>Solution</u> :-</h2>

Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.

  • Hence, we can see that, here, we have been given the linear equation be;

Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .

Hence,

x + 6x = 6

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x =  \frac{6}{7}  \\

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6(2)

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