Answer:
using Pythagoras theorem
Step-by-step explanation:
it's option c
<h3>
Answer: A) intersecting</h3>
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Work Shown:
Solve the first equation for y
x+y = ab
y = -x+ab
y = -1x + ab
slope = -1, y intercept = ab
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Solve for y in the second equation
bx - y = a
bx - y - a = 0
bx-a = y
y = bx - a
Slope = b, y intercept = -a
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The first equation has a slope of -1. The second equation has a slope of b.
Since b cannot equal -1, this means the two equations have different slopes. It is impossible for these two lines to be parallel, because parallel lines have equal slopes. The different slope values tell us the lines cross at exactly one point.
Answer:
Step-by-step explanation:
Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,
Rule to be followed,
A(x, y) → P(-y, x)
Therefore, A(1, 1) → P(-1, 1)
Similarly, B(3, 2) → Q(-2, 3)
C(2, 5) → R(-5, 2)
Triangle given in second quadrant will be the triangle PQR.
If the point P of triangle PQR is reflected across a line y = x,
Rule to be followed,
P(x, y) → X(y, x)
P(-1, 1) → X(1, -1)
Similarly, Q(-2, 3) → Y(3, -2)
R(-5, 2) → Z(2, -5)
Therefore, triangle given in fourth quadrant is triangle XYZ.
Slope = (y2 - y1)/(x2 - x1) = (10 - 70)/(5 - (-15)) = -60/(5 + 15) = -60/20 = -3
-2 x (3y - 8) would be the answer