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1 year ago

Which is equivalent to (3/125)*?

Mathematics

1 answer:

Musya8 [376]1 year ago

8 0

$\huge\text{Hey there!}$

$\huge\textbf{Question reads:}$

$\large\textbf{Which is equivalent to }\rm{\bf \dfrac{3}{125}}\large\textbf{ ?}$

$\huge\textbf{Solving for your fraction:}$

$\mathbf{\dfrac{3}{125}}$

$\mathbf{= \dfrac{3\times2}{125\times2}}$

$\mathbf{\approx \dfrac{3 + 3}{125 + 12{5}}}$

$\mathbf{= \dfrac{6}{250}}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\frak{\dfrac{6}{250}}}\huge\checkmark$

$\large\text{By the way, they are a lot more fractions that are equivalent to}\\\large\text{the given equation (}\rm{\dfrac{3}{125}}\large\text{) but we only labeled one that is the very}\\\large\text{first fraction that is equal to it. }$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h3>~ $\frak{Amphitrite1040:)}$ </h3>

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This 1 seems really complicated

Fofino [41]

The solution to this system set is: "x = 4" , "y = 0" ; or write as: [4, 0] .
________________________________________________________
Given:
________________________________________________________
y = - 4x + 16 ;

4y − x + 4 = 0 ;
________________________________________________________
"Solve the system using substitution" .
________________________________________________________
First, let us simplify the second equation given, to get rid of the "0" ;

→ 4y − x + 4 = 0 ;

Subtract "4" from each side of the equation ;

→ 4y − x + 4 − 4 = 0 − 4 ;

→ 4y − x = -4 ;
________________________________________________________
So, we can now rewrite the two (2) equations in the given system:
________________________________________________________

y = - 4x + 16 ; ===> Refer to this as "Equation 1" ;

4y − x = -4 ; ===> Refer to this as "Equation 2" ;
________________________________________________________
Solve for "x" and "y" ; using "substitution" :
________________________________________________________
We are given, as "Equation 1" ;

→ " y = - 4x + 16 " ;
_______________________________________________________
→ Plug in this value for [all of] the value[s] for "y" into {"Equation 2"} ;

to solve for "x" ; as follows:
_______________________________________________________
Note: "Equation 2" :

→ " 4y − x = - 4 " ;
_________________________________________________
Substitute the value for "y" {i.e., the value provided for "y"; in "Equation 1}" ;
for into the this [rewritten version of] "Equation 2" ;
→ and "rewrite the equation" ;

→ as follows:
_________________________________________________

→ " 4 (-4x + 16) − x = -4 " ;
_________________________________________________
Note the "distributive property" of multiplication :
_________________________________________________

a(b + c) = ab + ac ; AND:

a(b − c) = ab <span>− ac .
_________________________________________________
As such:

We have:
</span>
→ " 4 (-4x + 16) − x = - 4 " ;
_________________________________________________
AND:

→ "4 (-4x + 16) " = (4* -4x) + (4 *16) = " -16x + 64 " ;
_________________________________________________
Now, we can write the entire equation:

→ " -16x + 64 − x = - 4 " ;

Note: " - 16x − x = -16x − 1x = -17x " ;

→ " -17x + 64 = - 4 " ; Solve for "x" ;

Subtract "64" from EACH SIDE of the equation:

→ " -17x + 64 − 64 = - 4 − 64 " ;

to get:

→ " -17x = -68 " ;

Divide EACH side of the equation by "-17" ;
to isolate "x" on one side of the equation; & to solve for "x" ;

→ -17x / -17 = -68/ -17 ;

to get:

→ x = 4 ;
______________________________________
Now, Plug this value for "x" ; into "{Equation 1"} ;

which is: " y = -4x + 16" ; to solve for "y".
______________________________________

→ y = -4(4) + 16 ;

= -16 + 16 ;

→ y = 0 .
_________________________________________________________
The solution to this system set is: "x = 4" , "y = 0" ; or write as: [4, 0] .
_________________________________________________________
Now, let us check our answers—as directed in this very question itself ;
_________________________________________________________
→ Given the TWO (2) originally given equations in the system of equation; as they were originally rewitten;

→ Let us check;

→ For EACH of these 2 (TWO) equations; do these two equations hold true {i.e. do EACH SIDE of these equations have equal values on each side} ; when we "plug in" our obtained values of "4" (for "x") ; and "0" for "y" ??? ;

→ Consider the first equation given in our problem, as originally written in the system of equations:

→ " y = - 4x + 16 " ;

→ Substitute: "4" for "x" and "0" for "y" ; When done, are both sides equal?

→ "0 = ? -4(4) + 16 " ?? ;   → "0 = ? -16 + 16 ?? " ; → Yes! ;

{Actually, that is how we obtained our value for "y" initially.}.

→ Now, let us check the other equation given—as originally written in this very question:

→ " 4y − x + 4 = ?? 0 ??? " ;

→ Let us "plug in" our obtained values into the equation;

{that is: "4" for the "x-value" ; & "0" for the "y-value" ;

→ to see if the "other side of the equation" {i.e., the "right-hand side"} holds true {i.e., in the case of this very equation—is equal to "0".}.

→ " 4(0)  − 4 + 4 = ? 0 ?? " ;

→ " 0 − 4 + 4 = ? 0 ?? " ;

→ " - 4 + 4 = ? 0 ?? " ; Yes!
_____________________________________________________
→ As such, from "checking [our] answer (obtained values)" , we can be reasonably certain that our answer [obtained values] :
_____________________________________________________
→ "x = 4" and "y = 0" ; or; write as: [0, 4] ; are correct.
_____________________________________________________
Hope this lenghty explanation is of help! Best wishes!
_____________________________________________________

7 0

2 years ago

25 points!!!

professor190 [17]

Answer:

x+y=12

Step-by-step explanation:

First, substitute 3y for the spots with x:

2(3y) + 2y = 24

6y+ 2y = 24

8y= 24

y= 3

Then sub in 3 in the y place:

x= 3(3)

x= 9

Then plug in the x and y values in the equation:

9 + 3 =12

Good Luck!!!

plz mark me Brainliest!

3 0

2 years ago

Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m

andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$A_1 = 67.58 \ in^2$

$A_2 =415.4 \ ft^2$

$A_3 = 8.48 \ cm^2$

$A_4 = 480.38 \ m^2$

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

$A = \frac{\theta}{360} * \pi r^2$

Now at $r_1 = 11 in$ and $\theta_1 = 64^o$

$A_1 = \frac{64}{360} * 3.142 * 11^2$

$A_1 = 67.58 \ in^2$

Now at $r_2 = 20 ft$ in and $\theta_2 = 119 ^o$

$A_2 = \frac{119}{360} * 3.142 * 20^2$

$A_2 =415.4 \ ft^2$

Now at $r_3 = 6.5 cm$ and $\theta_3 = 23 ^o$

$A_3 = \frac{23}{360} * 3.142 * 6.5 ^2$

$A_3 = 8.48 \ cm^2$

Now at $r_4 = 14.2 m$ and $\theta_4 = 360 -87 = 273 ^o$

$A_4 = \frac{273}{360} * 3.142 * 14.2^2$

$A_4 = 480.38 \ m^2$

6 0

3 years ago

PLS HELPPPP<br> Solve 3x2 + 18x + 15 = 0 by completing the square. <br> I CANT FIND REAL ANSWER!

Dmitriy789 [7]

Answer:

x = − 1 , − 5

7 0

3 years ago

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Which of the following describes the polynomial function ??? HELP

JulsSmile [24]

Answer:

B. The function has an even degree.

Step-by-step explanation:

We have been given an image of a polynomial function. We are asked to choose the correct options about our given polynomial.

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Upon looking at our given graph, we can see that it is an upward opening parabola, so leading coefficient can't be negative, therefore, option A is not true.

B. The function has an even degree.

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Since our function never intersects x-axis, therefore, function has no x-intercept and option D is incorrect as well.

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3 years ago