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Nookie1986 [14]
3 years ago
11

1-sinA+cosA / sinA+cosA-1 = 1+cosA/sinA​

Mathematics
1 answer:
Art [367]3 years ago
6 0

<u>Solution:</u>

\dfrac{\left[\left(\sin ^{2} A+2  \times \sin A  \times (1-\cos A)+(1-\cos A)^{2}\right]\right.}{\left[\left(1-\cos ^{2} A\right)-(1-\cos A)^{2}\right]}

\dfrac{\left[\left(1-\cos ^{2} A\right)+2  \times  \sin A  \times (1-\cos A)+(1-\cos A)^{2}\right]}{\left[(1-\cos A)(1+\cos A)-(1-\cos A)^{2}\right]}

\dfrac{(1-\cos A)[1+\cos A+2 \sin A+1-\cos A]}{[1-\cos A][1+\cos A-1+\cos A]}

\dfrac{[2+2 \sin A]}{[2  \times  \cos A]}

\dfrac{2(1+\sin A)}{2 \times \cos A}

\dfrac{1+\cos A}{\sin A}

<u>Hence Proved.</u>

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