Answer:
The probability under the given conditions is found:
P(7) = 0.079
Step-by-step explanation:
Let x be the number of adults who believe in reincarnation.
Adults randomly selected = 8
percentage of adult believe in reincarnation = 40% = 0.4
x follows binomial distribution:
P(x) =
where
n= total people random people selected = 8,
x = selected for the part = 7,
p = probability given = 0.4
P(7) =
P(7)= (8)(0.0164)(0.6)
P(7) = 0.07872
Rounding off to 3 decimal positions
P(7) = 0.079
Answer:
C. H0 : p = 0.8 H 1 : p ≠ 0.8
The test is:_____.
c. two-tailed
The test statistic is:______p ± z (base alpha by 2)
The p-value is:_____. 0.09887
Based on this we:_____.
B. Reject the null hypothesis.
Step-by-step explanation:
We formulate null and alternative hypotheses as proportion of people who own cats is significantly different than 80%.
H0 : p = 0.8 H 1 : p ≠ 0.8
The alternative hypothesis H1 is that the 80% of the proportion is different and null hypothesis is , it is same.
For a two tailed test for significance level = 0.2 we have critical value ± 1.28.
We have alpha equal to 0.2 for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28
The test statistic is
p ± z (base alpha by 2)
Where p = 0.8 , q = 1-p= 1-0.8= 0.2
n= 200
Putting the values
0.8 ± 1.28
0.8 ± 0.03620
0.8362, 0.7638
As the calculated value of z lies within the critical region we reject the null hypothesis.