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3 years ago

∠a = 5x – 5º. ∠ b = 3x + 13º. Solve the x then find the measure of ∠ b.

Mathematics

1 answer:

Scilla [17]3 years ago

7 0

Answer: X= 4 and angle B = 26

Step-by-step explanation: 5x-5=3x+13

Subtract 3x and add 5 to both sides. Divide both sides by 2.

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What number is the same as distance from 0 on a number line as 1 1/2

Elena-2011 [213]

Answer: What is the distance from 0 on a number line called?

The distance between a number's place on the number line and 0 is called the number's [absolute value]. To write the absolute value of a number, use short vertical lines (|) on either side of the number.

Step-by-step explanation:

Here's a hint. I hope this helps.

3 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.