Area of the shaded sector = (120/360) * pi * 10^2
= 104.72 square units
Area of the other sector = 2 * 104.72 = 209.44 sq units
R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
The answer is
Each roll has a 0.333 probability of being composite.
<em>(I just took the test,
B was the answer)</em>
Answer:
The equation is true/ or an identity
Step-by-step explanation:
Plug in 7 for x, you get
2(7)+3=17
14+3=17
17=17
The mean of the answer is 20.5 because you add all of the number together and divide by 6 because there's 6 numbers.
I'm sorry, but I don't know how to do the standard deviation...
Hope this helped!
