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Scrat [10]
2 years ago
14

Will give correct answer brainliest​

Mathematics
1 answer:
Elodia [21]2 years ago
8 0

Answer:

2. Division property of equality

3. x+1 = -4

4. Subtraction property of equality

5. x = -5

Step-by-step explanation:

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What are the next three terms in the sequence -27, -19, -11, -3, 5, ...?
ddd [48]

Answer:

13, 21, 29

Step-by-step explanation:

the difference is 8

so add 8 to last numbers

3 0
3 years ago
Read 2 more answers
Graph the inequality in the coordinate plane. x<-6
puteri [66]

Answer:

You would make a dotted vertical line running through -6 on the horizontal or x axis. The shading would go to the left side of the line since x is less than -6 and the line is dotted because it is only less than and not equal to.

Step-by-step explanation:

See image

5 0
4 years ago
Which value for □ will make the equation true? 12+(6×□)=72
marusya05 [52]

Answer:

i think its 30.

Step-by-step explanation:

Brainliest?

6 0
3 years ago
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How can I divide decimals
shusha [124]
You can write the problem with a division box, move the divisor decimal point the amount of spaces that it would take to make the number whole. Move the decimal if the dividend the same amount of spaces as the divisor. Move the decimal point directly up above the division bar, divide, check your work
4 0
3 years ago
Read 2 more answers
Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f
nata0808 [166]
Via Lagrange multipliers:

L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)
L_x=2xy+1+\lambda y=0
L_y=x^2+1+\lambda x=0
L_\lambda=xy-5=0

\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y
xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x

\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}
xy=5\implies y=\pm\sqrt{30}

At these points, we get local minima of f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}.

- - -

Another way to do this is to make f(x,y) a function independent of y, which is made possible by the constraint.

xy=5\implies y=\dfrac5x
\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x
\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}

and so on.
8 0
3 years ago
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