what r we doing this question to(*・～・*)
X = 47 + 9y
xy = 1860
y(47 + 9y) = 1860
47y + 9y² = 1860
9y² + 47y - 1860 = 0
> using a quadratic equation solver on a calculator but you can also use the quadratic equation = [-b+/- √(b²-4ac)]/(2a)
> only integer solution is x = 12
12y = 1860
y = 155
integers are 12 and 155
I'm assuming you mean negative integers and mixed. -3--3=? When to negatives are back to back it turns in to a positive number. The equation becomes -3+3=0.
Adding 2 negative numbers will always result in a negative value. -3+-3=-6.
A negative times a negative is always a positive . -2x-2=4
A positive integer times a negative integer will be a negative value. -3x4=-12.
A negative divided by a negative is a negative. -12/-2=-6
A positive divided by a negative is a negative. 9/-3=-3
I believe you haven't included the system of equations for us to solve.
However, I will tell you that you need to solve for one variable in an equation and substitute that into the other equation.
For example:
x = yz; z = x/y
a = zb; a = (x/y)b
Hope this helps!
The answer is -25
3-8=-5
-5*5=-25
