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2 years ago

21 ≤ 2x + 3 = How do you work this out? And what is the answer? :)

Mathematics

2 answers:

nadya68 [22]2 years ago

7 0

Answer:

Step-by-step explanation:

21≤2x+3
21-3≤2x
18≤2x
divide both side by 2
therefore the answer
x≥9

Igoryamba2 years ago

4 0

Just use app called Socratic will help out

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Find the measure of CD

Marysya12 [62]

Answer:

Step-by-step explanation:

The central angle of the segment is 60 degrees. Line CD is the same length as the radius and there are 3 sides with the same length. The triangle so formed is equilateral and the apex angle is 60 degrees which is the central angle.

The measure of arc CD is 60 degrees.

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2 years ago

What is this figure?

Wewaii [24]

Answer:

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Step-by-step explanation:

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2 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

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2 years ago

Please help!!<br> Will mark brainliest

Over [174]

Y would equal to -5. hope this helps

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2 years ago

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katen-ka-za [31]

When a circle's diameter is 1, its circumference is π.

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