Question

how many kilograms of pure water is to be added to 100 kilograms of a 30% saline solution to make it a 10% saline solution

Answer 1

Answer:

  200 kg

Step-by-step explanation:

If w is the amount of water added, then the concentration of the solution is ...

  salt/solute = 100(0.30)/(100 +w) = 0.10

  30 = 10 +0.10w . . . . . simplify

  20 = 0.10w . . . . . . . . subtract 10

  20/0.10 = w = 200 . . . . divide by 0.10

200 kg of water must be added to dilute the solution to 10%.