Using distance between two points to find the lengths of the edges of the triangle, the correct option is:
b. Isosceles
The distance between two points,
and
, is given by:
![d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D)
Vertex D is translated 4 units to the right is (9,8).
The lengths of the edges are:
![DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}](https://tex.z-dn.net/?f=DN%20%3D%20%5Csqrt%7B%289%20-%20%28-3%29%29%5E2%20%2B%20%288%20-%2010%29%5E2%7D%20%3D%20%5Csqrt%7B12%5E2%20%2B%202%5E2%7D%20%3D%20%5Csqrt%7B148%7D)
![DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}](https://tex.z-dn.net/?f=DO%20%3D%20%5Csqrt%7B%289%20-%20%28-3%29%29%5E2%20%2B%20%288%20-%206%29%5E2%7D%20%3D%20%5Csqrt%7B12%5E2%20%2B%202%5E2%7D%20%3D%20%5Csqrt%7B148%7D)
![NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4](https://tex.z-dn.net/?f=NO%20%3D%20%5Csqrt%7B%28-3%20-%20%28-3%29%29%5E2%20%2B%20%2810%20-%206%29%5E2%7D%20%3D%20%5Csqrt%7B0%5E2%20%2B%204%5E2%7D%20%3D%204)
<u>Two edges of the same length</u>, hence, it is an isosceles triangle, given by option b.
You can learn more about distance between two points at brainly.com/question/18345417
Answer:
$212.40
Step-by-step explanation:
180+ (180* 18%)= Total Cost
180+ 32.40= Total Cost
212.40= Total Cost
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