3 years ago

How do I solve for the missing length? Please explain!! I’m struggling

Mathematics

1 answer:

REY [17]3 years ago

5 0

Let call it x
x/4=4/2
->x=8

You might be interested in

Geometry help greatly needed, check photo for more information! <3

vlabodo [156]

Answer:

$\huge\boxed{\sf x = 55\°}$

Step-by-step explanation:

When a quadrilateral is inscribed in a circle, the opposite angles of it add up to 180 degrees.

Here,

∠DCB + ∠DAB = 180 (Opposite angles of a quad inscribed in a circle.)

<u>Given that:</u> ∠DCB = 135° and ∠DAB = x

135 + x = 180

Subtract 135 to both sides

x = 180 - 135

x = 55°

$\rule[225]{225}{2}$

Hope this helped!

8 0

2 years ago

G(t) = −3t^3 − 4t f (t) = 4t − 4 Find g(t) + f (t)

Anit [1.1K]

Answer:

cDGKSc h

Step-by-step explanation:

8 0

2 years ago

For the inequality, find TWO values for x that make the inequality true: 5x<2

dangina [55]

Answer:

a and c

Step-by-step explanation:

5(-2)<2

-10<2

5(-5)<2

-25<2

7 0

2 years ago

Evaluate expression 8z+3;z=8

Oxana [17]

The answer would be 67

7 0

3 years ago

Read 2 more answers

(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28

Veronika [31]

$(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}$

4 0

3 years ago

Read 2 more answers