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In-s [12.5K]
2 years ago
9

Please help me on this question thanks ! I will mark you brainliest

Mathematics
1 answer:
igomit [66]2 years ago
7 0

Answer:

3x+2°=65° (vert opp angles)

3x=65°-2°

=63°

x=63÷3

=21

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The formula for the volume of a sphere is v=4/3r3 what is the formula solved for r?
Salsk061 [2.6K]

Answer:

(3 V/ 4 pi) ^(1/3) =  r

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

We want to solve for r

Multiply each side by 3/4

3/4 V = 4/3*3/4 pi r^3

3/4 V = pi r^3

Divide each side by pi

3/4 V/ pi = pi/pi r^3

3 V/ 4 pi =  r^3

Take the cube root of each side

(3 V/ 4 pi) ^(1/3) = ( r^3) ^1/3

(3 V/ 4 pi) ^(1/3) =  r

5 0
3 years ago
Please help I found this one a bit confusing ​
Brums [2.3K]

Answer:

7.2

Step-by-step explanation:

To reach point D from point C, you need to add 4 to the x-value of point C and take away 6 from the y-value. These numbers are the sides of the hypothetical triangle.

The Pythagorean Theorem states that a^2+b^2=c^2. If we plug the side lengths in for a and b, we get 4^2 + 6^2 = c^2. This can be simplified to 16+36=c^2, or 52 = c^2. If we root both sides, we find that c is equal to \sqrt{52}, which is slightly more than 7, at around 7.2.

4 0
2 years ago
Simplify the following expression:<br> 3X(4-1) + (6+21)
Ilya [14]

Answer:

9x+27

Step-by-step explanation:

3x(4−1)+6+21

=9x+6+21

Combine Like Terms

=9x+6+21

=(9x)+(6+21)

=9x+27

3 0
3 years ago
Read 2 more answers
Occasionally a savings account may actually pay interest compounded continuously. For each deposit, find the interest earned if
Ugo [173]

1. Occasionally a savings account may actually pay interest compounded continuously. For each​ deposit, find the interest earned if interest is compounded​ (a) semiannually,​ (b) quarterly,​ (c) monthly,​ (d) daily, and​ (e) continuously. Use 1 year = 365 days.

Principal ​$1031

Rate 1.4%

Time 3 years

Answer:

a) $ 44.07

b) $ 44.15

c) $ 44.20

d) $ 44.22

e) $ 44.22

Step-by-step explanation:

The formula to find the total amount earned using compound interest is given as:

A = P(1 + r/n)^nt

Where A = Total amount earned after time t

P = Principal = $1031

r = Interest rate = 1.4%

n = compounding frequency

t = Time in years = 3 years

For each​ deposit, find the interest earned if interest is compounded

(a) semiannually

This means the interest is compounded 2 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/2) ^2 × 3

A = 1031 (1 + 0.007)^6

A = $ 1,075.07

A = P + I where

I = A - P

I = $1075.07 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.07

​(b) quarterly

This means the interest is compounded 4 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/4) ^4 × 3

A = 1031 (1 + 0.014/4)^12

A = $ 1,075.15

I = A - P

I = $1075.15 - $1031

A = P + I where

P (principal) = $ 1,031.00

I (interest) = $ 44.15

(c) monthly,

​ This means the interest is compounded 12 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/12) ^12 × 3

A = 1031 (1 + 0.014/12)^36

A = $ 1,075.20

A = P + I where

I = A - P

I = $1075.20 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.20

(d) daily,Use 1 year = 365 days

This means the interest is compounded 365 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/365) ^2 × 3

A = 1031 (1 + 0.00365)^365 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

(e) continuously. .

This means the interest is compounded 2 times in a year

Hence:

A = Pe^rt

A = 1031 × e ^0.014 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

5 0
3 years ago
99999999÷777777777÷888888888888×8888889999=<br><br>EXPLAIN NO CHEATING
Zarrin [17]

Answer:

0.00128571443

Step-by-step explanation:

go left to right

4 0
3 years ago
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