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vesna_86 [32]
2 years ago
7

The fifth-grade teachers at Washington High School are decorating bulletin boards to get

Mathematics
1 answer:
Yuki888 [10]2 years ago
6 0

The teacher will use 3 rolls only to have perfect measurements.

1 yard = 3 feet

4 large bulletin boards are there each needing 9 yards of border.
That means 4 large bulletin boards in total need

9×4 yards of border

= 36 yards of border

= 108 feet of border

Also, there is a small bulletin board that only needs 12 feet border

Hence, in total there is a need for

108 + 12 = 120 feet border.

The border is sold in 40-foot rolls.
Hence, there is a need for 120/40 rolls

i.e. 3 rolls

Hence, the teacher will use 3 rolls only.  

Learn more about measurements here-

brainly.com/question/15658113

#SPJ10

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josh , James and John share sweets in ratio 1:2:4 . Josh has 9 sweets less than John . how many sweets does John have ?​
disa [49]

Answer:

12

Step-by-step explanation:

1:2:4

let josh=1x

james=2x

john=4x

josh has nine sweets less than john

4x-1x=9

3x=9

x=3

john's sweet=4x

4(3)=12

3 0
2 years ago
Can you answer the question please I really need help
LenaWriter [7]
The answer is 1 7/30 hope this helps
5 0
3 years ago
Pleas someone help me with this it's my last question
ruslelena [56]

Answer:

we need to find out if the following get x = 2 as a final product

-2(x-4) = 4

-2x + 8 = 4

-2x = -4

x = 2

so it is a solution

26/x = 13

26 = 13x

x = 26/13

x = 2

so it’s a solution

-3.8x = -7.4

x = 7.4/3.8 ≠ 2

you get ≈ 1.95

so it’s not a solution

4(x-1) - 3(x-2) = -8

4x - 4 - 3x + 6 = -8

x + 2 = -8

x = -10

so it’s not a solution

5 0
2 years ago
Read 2 more answers
5/8-11/20=?<br><br> Help what’s the answer I’m stuck on finding the LCM of the denominators
zhannawk [14.2K]

Answer:

3/40

Step-by-step explanation:

  • \frac{5}{8} - \frac{11}{20}
  • \frac{25}{40} - \frac{22}{40} (LCM is 40)
  • \frac{25-22}{40}
  • \frac{3}{40}

Therefore, the answer is 3/40!

4 0
2 years ago
Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv
Oliga [24]

Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

Here, in 2t years, there will be 2t + 1 terms in the geometric series including the initial term. Thus in the above series, a = 10, r = 4 and n = 2t + 1. Then the population of the Zebra mussels after 2t years is the (2t +1)st term of the geometric series I.e. 10* ( 42t)                  

In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

1000000 = 10 * (42t) or, 100000= 42t or,105 = 42t    Taking logarithms of both sides, we have 5 log 10 = 2t log 4 or, t = (5log10)/(2log4) = 5/1.20 years or (5/1.20) * 12 months = 50 months, i.e. 4 years and 2 months.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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