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3 years ago

Can someone help me with these 2 questions?

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

5 0

Answer:

3: x = 3 4: y = 8

Step-by-step explanation:

Problem 3:

Because of the lines on each side of the rhombus, that shows you that all of those lines are congruent with each other, meaning they are all the same length. So since one side equals the other, you can equal one of the equations on one side to another equation on another side. EX: x+5 = 3x-1. And then you solve that through multi-step equations.

Problem 4:

Just like on Problem 3, due to the little dashes going through the sides of the rectangle, the sides are congruent (the same length) as one another. Except the sides with one dash are not congruent with the sides with two dashes. But if you equal 2y and y+8, then you can solve that through multi-step equations again and get y = 8 since they are congruent with each other (due to the singular dashes running through their sides).

Hope this helped!

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(4x + 3) (3x^2 - 5x + 6)

Liula [17]

Answer:

12x^3 - 11x^2 + 9x + 18

Step-by-step explanation:

12x^3 - 20x^2 + 24x + 9x^2 -15x + 18

Combine like terms

12x^3 - 11x^2 + 9x + 18

4 0

3 years ago

Angie divides the polynomial function f(x)=x3+3x2−7x−21 by (x + 3). What can she conclude from the fact that the remainder is eq

iren [92.7K]

Answer:

See below

Step-by-step explanation:

Given function

f(x)=x³ + 3x²- 7x - 21

We can find its factors:

x³ + 3x² - 7x - 21 =
x²(x + 3) - 7(x + 3) =
(x² - 7)(x + 3)

We can conclude that the given polynomial function is fully divisible by (x + 3) and the quotient is (x² - 7)

Also one of zeros of the function is -3

8 0

3 years ago

The function f(x)=/-x is shown on the graph

Katyanochek1 [597]

we know that

For the function shown on the graph

The domain is the interval--------> (-∞,0]

$x\leq0$

All real numbers less than or equal to zero

The range is the interval--------> [0,∞)

$y\geq 0$

All real numbers greater than or equal to zero

Statements

case A) The range of the graph is all real numbers less than or equal to $0$

The statement is False

Because the range is all numbers greater than or equal to zero

case B) The domain of the graph is all real numbers less than or equal to $0$

The statement is True

See the procedure

case C) The domain and range of the graph are the same

The statement is False

Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero

case D) The range of the graph is all real numbers

The statement is False

Because the range is all numbers greater than or equal to zero

therefore

the answer is

The domain of the graph is all real numbers less than or equal to $0$

8 0

3 years ago

Read 2 more answers

Consider the equation 21 = m + 14 1/6. Which step will help to solve this equation? A add 14 1/6 on both sides of the equation.

Furkat [3]

Answer:

B. subtract

Step-by-step explanation:

Subtracting is the opposite of adding which is what is originally in the equation, by subtracting you are canceling out the 14 1/6

7 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago