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2 years ago

20 POINTS

Mathematics

1 answer:

kenny6666 [7]2 years ago

7 0

Answer:

c = 75.36 cm

Step-by-step explanation:

$radio = diameter/2 = 24/2 = 12 cm\\$

$c=2\pi r=2(3.14)(12)=75.36cm$

Hope this helps

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I don't really get it. it would be amazing if you help and show work

eimsori [14]

Change of y / over change of x
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B is your correct answer
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7 0

3 years ago

Read 2 more answers

If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=8/17and cos b=1

n200080 [17]

Recall the sum identity for cosine:

cos(a + b) = cos(a) cos(b) - sin(a) sin(b)

so that

cos(a + b) = 12/13 cos(a) - 8/17 sin(b)

Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,

cos²(a) + sin²(a) = 1 ⇒ cos(a) = √(1 - sin²(a)) = 15/17

cos²(b) + sin²(b) = 1 ⇒ sin(b) = √(1 - cos²(b)) = 5/13

Then

cos(a + b) = 12/13 • 15/17 - 8/17 • 5/13 = 140/221

6 0

2 years ago

Please help!! Will give brainliest

hichkok12 [17]

Answer:

HELLO! im confused do u want us to answer all of them:D?

Step-by-step explanation:

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3 years ago

Victoria has $200 of her birthday gift money saved at home, and the amount is modeled by the function h(x) = 200. She reads abou

svlad2 [7]

Solution :

Amount of money Victoria has = $200

The amount modelled by function = h(x) = 200

According to the function,

s(x) = (1.05)x - 1

It means that the total amount of the interest that Victoria will receive s(x) is equal to original amount of $200 which multiplied by the rate of interest (1.05) and then multiplied by the time that Victoria keeps the money in the bank (x) minus 1.

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3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$