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Yuliya22 [10]
3 years ago
8

Sally bought 4 boxes of pens for $6 each and 7 packages for $7 each. Find the amount sally spent on pens and paper.

Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

73  is total amount

Step-by-step explanation:

Have a great day!

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Anuta_ua [19.1K]

Answer:

increase because 324 >>>>> 239

percentage: 324/239 = 135%

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Which lines are parallel? Why?
Shtirlitz [24]

9514 1404 393

Answer:

  C) c || d by converse of corresponding angles

Step-by-step explanation:

Only corresponding angles where transversal b crosses lines c and d are shown. All answer choices involving a||b or interior angles can be eliminated from consideration.

The "corresponding angle" theorem tells you corresponding angles are congruent if the lines are parallel.

The converse of that theorem tells you the lines are parallel if the corresponding angles are congruent. Here, the angles are shown congruent, so the "converse" theorem applies.

8 0
3 years ago
Which function is best represented by this graph?
zalisa [80]

Answer:

B- y=\frac{1}{4}x-2

Step-by-step explanation:

To look at the slope you can count over four and then up one and its at the next point.

Also, the place on the y-axis is at -2

So, b makes the most since :)

Hope this helps :) (if it does, brainliest??)

7 0
3 years ago
A brother is 3 years older than his sister. Five years ago, the ratio of their ages was 4 : 3. Find the boy age.
Wewaii [24]
17 years old
12:9
12 + 5 is 17
5 0
3 years ago
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
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