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3 years ago

Urgent please help quick!!!

Mathematics

1 answer:

Radda [10]3 years ago

5 0

Answer:

$x=-1\\y=-1$

Step-by-step explanation:

$5x+5y=-10\\3x-7y=4$

Let's solve the first equation for either x or y. I'll do it for x.

$5x+5y=-10$

Begin by subtracting 5y.

$5x=-5y-10$

Now divide by 5.

$x=\frac{-5y}{5}-\frac{10}{5}$

Simplify:

$x=-y-2$

Now substitute x in the second equation for this value.

$3x-7y=4\\3(-y-2)-7y=4$

Distribute;

$-3y-6-7y=4$

Add 6

$-3y-7y=4+6$

Combine like terms;

$-10y=10$

Divide by -10.

$y=\frac{10}{-10}\\ y=-1$

-----------------------------------------------------------------------------------------------------------

Take this value of y and replace it in the first equation to find the value of x.

$5x+5y=-10\\5x+5(-1)=-10\\5x-5=-10\\5x=-10+5\\5x=-5\\x=\frac{-5}{5}\\ x=-1$

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3 years ago

Factorise x^3 - 2x^2 -x+2

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3 years ago

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What is the MAD of the numbers (Round to the nearest tenth.) 9,7,6,8,6,6

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Step-by-step explanation:

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4 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) Now, here sample of NBA players is 26 so n = 26.

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

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4 years ago

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andrezito [222]

Answer:

Step-by-step explanation:

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