Question

A 250.ml sample of water was

Answer 1

Answer: The solubility of this gaseous solute will be,

Explanation :

First, we have to calculate the concentration of solute.

Now we have to calculate Henry's law constant.

Using Henry's law :

where,

C = concentration of solute =

p = partial pressure = 27.59 kPa

= Henry's law constant =?

Now put all the given values in the above formula, and we get:

Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.

Therefore, the solubility of this gaseous solute will be,