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Iteru [2.4K]
2 years ago
7

A 250.ml sample of water was

Chemistry
1 answer:
gulaghasi [49]2 years ago
4 0

Answer: The solubility of this gaseous solute will be,

Explanation :

First, we have to calculate the concentration of solute.

Now we have to calculate Henry's law constant.

Using Henry's law :

where,

C = concentration of solute =

p = partial pressure = 27.59 kPa

= Henry's law constant =?

Now put all the given values in the above formula, and we get:

Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.

Therefore, the solubility of this gaseous solute will be,

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