Question

How many grams of P2Cl5 are produced if 2.00 moles of P reacts with an excess of Cl2?

Answer 1

Answer:

$m_{P_2Cl_5 }=239.2125gP_2Cl_5$

Explanation:

Hello there!

In this case, according to the reaction:

$4P+5Cl_2\rightarrow 2P_2Cl_5$

Thus, since there is a 4:2 mole ratio of P to P2Cl5 and the molar mass of the later is 239.2125 g/mol, we obtain the following mass as the produced one:

$m_{P_2Cl_5 }=2.00molP*\frac{2molP_2Cl_5}{4molP} *\frac{239.2125gP_2Cl_5 }{1molP_2Cl_5} \\\\m_{P_2Cl_5 }=239.2125gP_2Cl_5$

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