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Novosadov [1.4K]
4 years ago
12

Draw the major condensation product obtained by treatment of ethyl 3-methylbutanoate with sodium ethoxide in ethanol.

Chemistry
1 answer:
dexar [7]4 years ago
6 0

Answer:

ethyl 3-ethoxy-3-hydroxy-2-isopropyl-5-methyl hexanoate

Explanation:

In this case, we have a <u>very strong base</u> (sodium ethoxide). Therefore, this compound will remove a hydrogen from ethyl 3-methyl butanoate generating a <u>carbanion</u>.

This carbanion, can attack <u>another ethyl 3-methyl butanoate molecule </u>on the carbonyl group generating a new C-C bond and producing a negative charge in the oxygen.

Then the ethanol can <u>protonate</u> the molecule generating an "OH" group and the ethoxide.

See figure 1

I hope it helps!

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