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2 years ago

Explain how the rate of diffusion of a gas is related to its molar mass.

Chemistry

1 answer:

Alex73 [517]2 years ago

5 0

The molar mass of the unknown gas is 450.56 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

How to determine the molar mass of the gas

Rate of unknown gas (R₁) = R
Rate of CO₂ (R₂) = 3.2R
Molar mass of CO₂ (M₂) = 44 g/mol

Molar mass of unknown gas (M₁) =?

R₁/R₂ = √(M₂/M₁)

R / 3.2R = √(44 / M₁)

1 / 3.2 = √(44 / M₁)

Square both side

(1 / 3.2)² = 44 / M₁

Cross multiply

(1 / 3.2)² × M₁ = 44

Divide both side by (1 / 3.2)²

M₁ = 44 / (1 / 3.2)²

M₁ = 450.56 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

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3 years ago

6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)

scoray [572]

Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

Heat= 92.048 kJ
Mass of water = ?
Initial temperature of water= 34 ºC
Final temperature of water= 100 ºC
Specific heat of water = 4.186 $\frac{J}{gC}$

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× (100 °C -34 °C)

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× 66 °C

m= 92.048 kJ ÷ (4.186 $\frac{J}{gC}$ × 66 °C)

<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 $\frac{g}{mole}$ , that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as: