Outcome on winning = $100 - $20 = $80
Outcome on losing = $20
Probability of winning = 1/6
Probability of losing = 5/6
Expected Value = 1/6 (80) +5/6(-20) = -3.333
This shows on average from each game, the game earns $ 3.333.
So, if 1000 such games are played, the game will earn 1000 x 3.33 = $3330
So, the answer to this question is option A
Answer:
4,3
Step-by-step explanation:
1 is milli. 2 is kilo. 3 is centi. 4 is meter. 5 is kilogram. 6 is liter.
Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
Answer:
5.5 inches
Step-by-step explanation: