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True [87]
2 years ago
12

What is the value of the logarithm below? (Round your answer to two decimal

Mathematics
1 answer:
Allushta [10]2 years ago
5 0
A. 0.58 it’s that man I did this it was very easy
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There is a game at the carnival that costs $20 to play. There are two outcomes: either you win $100 , or you lose. To play you r
Taya2010 [7]
Outcome on winning = $100 - $20 = $80
Outcome on losing = $20

Probability of winning = 1/6
Probability of losing = 5/6

Expected Value = 1/6 (80) +5/6(-20) = -3.333

This shows on average from each game, the game earns $ 3.333.

So, if 1000 such games are played, the game will earn 1000 x 3.33 = $3330 

So, the answer to this question is option A
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Analyze the graph. Use the triangle to find the slope, m, of the line
Alex17521 [72]

Answer:

4,3

Step-by-step explanation:

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3 years ago
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Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

n(U)=27

n(A)=7

n(B)=18

n(A'\cap B')=7

We know that,

n(A\cup B)=n(U)-n(A'\cap B')

n(A\cup B)=27-7

n(A\cup B)=20

Now,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=7+18-n(A\cap B)

n(A\cap B)=7+18-20

n(A\cap B)=25-20

n(A\cap B)=5

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}

\text{Probability}=\dfrac{5}{27}

Therefore, the required probability is \dfrac{5}{27}.

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(Circumference or circles)<br> explain your answer so I can understand
Ghella [55]

Answer:

5.5 inches

Step-by-step explanation:

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