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Kay [80]
3 years ago
13

Name all segments skew to HI

Mathematics
1 answer:
Kipish [7]3 years ago
8 0
The answer is d because non of them intersect skew HI
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What scale factor was applied to the first rectangle to get the resulting image?
madam [21]

Answer:

The scale factor for the resultant rectangle is\frac{2}{5} units.

Step-by-step explanation:

Given two rectangles with sides 3 units and 7.5 units.

We have to find the scaling factors so that we can obtain bigger rectangle of 7.5 units from smaller rectangle of 3 units.

Scale factor is defined as the ratio  of corresponding side of given figure to the corresponding side of resulting figure.

That is \text{Scale factor}=\frac{\text{length of side of given figure}}{\text{length of side of resulting figure}}

Here, \text{Scale factor}=\frac{\text{length of side of given rectangle }}{\text{length of side of resulting rectangle}}

\text{Scale factor}=\frac{3}{7.5}=\frac{2}{5}

Hence, the scale factor for the resultant rectangle is\frac{2}{5} units.  

4 0
3 years ago
7.2 is 15% of what number?​
polet [3.4K]

Answer:

48

Step-by-step explanation:

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BaLLatris [955]

If There is a math equation you can use math-way.

Also it would help if you can take a better picture.

Once you take a better picture I promise i will try my best to answer the question.

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Proof true or false: For all integers a,b,and c,if ab|c then a|c and b|c
olya-2409 [2.1K]

Answer with explanation:

It is given that for three integers , a, b and c, if

              \frac{ab}{c}\rightarrow then, \frac{a}{c} \text{or} \frac{b}{c}

Since , a b is divisible by c , following are the possibilities

1.→ a and b are prime integers .Then , c will be prime number either equal to a or b.

2.→a and b are not prime integers ,then any of the factors of a or b will be equal to c.For example:

 ⇒a=m × n

 b=p × q× c

or,

⇒a=u×v×c

b=s×t

So, whatever the integral values taken by a, and b, if \frac{ab}{c} then either of  \frac{a}{c} \text{or} \frac{b}{c} is true.

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3 years ago
Help please with math
yuradex [85]

Here you go, sometimes, quizlet is there with just the right info. Ur welcome.

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3 years ago
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