vertex form of a parabola
y= a(x-h)^2 +k
y =a(x--3)^2 +2
y = a(x+3)^2 +2
Choice B
Answer:
6 stuffed animals
Step-by-step explanation:
if 1/4= 1 then 1x6= 1 1/2
<span>The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
Because this is not an integration with specific bounds, you must include a constant at the end.
In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.</span>
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
Step 1
Find the length of MD
we know that
The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle
so
In this problem
------> is the radius of a circle inscribed inside the triangle
we have that
therefore
Step 2
Find the length of DC
we know that
In the right triangle MDC
Applying the Pythagoras theorem
we have
substitute
Answer:
Point B = (-8 , -2) ⇒ the second answer
Step-by-step explanation:
∵ The figure ABCD is reflected across the x-axis
∴ The sign of y-coordinates of each point will change
Ex: If the point (x , y) reflected across the x-axis
its image will be (x , -y)
∵ B' = (-8 , 2)
∴ B = (-8 , -2) ⇒ the second answer
