1) Circumference: C = D × π = 40 × 3.14 = 125.6
Area: 
2) Perimeter: P = 10.82 +10.82 + 12 + ( 12 . 3,14 )/2 = 52.48 mm
Area: 
ok done. Thank to me :>
Answer:
- ΔHJK shows G as the orthocenter
- Show A.F is the median of BC
- 18
Step-by-step explanation:
1) This is a vocabulary question. The <em>orthocenter</em> is the point where the altitudes intersect. Of course, each altitude is a segment from a vertex that is perpendicular to the opposite side of the triangle.
Perhaps it could be useful to remember the prefix ortho- means perpendicular, as in <em>orthogonal</em>. Each altitude is perpendicular to one of the sides of the triangle.
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2) To do this proof, you would find midpoints of segments AB and AC, write the equations of the lines through them from the opposite vertex, then solve those equations to find point G. You would then write the equation for line AG and find its intersection point with segment BC (point F). The last step is to show that point F is the midpoint of BC. (It might be easier to show that midpoint F is on line AG.)
The closest answer choice, though poorly worded, is the last one: show A.F is the median of BC.
(Strictly speaking, a line segment (A.F) is not a median of a line segment (BC), but can be a median of a <em>triangle</em>, or a <em>bisector</em> of a line segment.)
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3) The centroid divides the median into parts with the ratio 2:1. That is, the shorter part differs from the longer one by 2-1 = 1 ratio unit. If those parts differ in length by 6 measurement units, then one ratio unit must be 6 measurement units. The total length of the median is 2+1 = 3 ratio units, or 3×6 measurement units = 18 measurement units.
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<em>Comment on A.F</em>
Brainly thinks the name of the segment starting with A and ending with F is a "bad word" so won't let it be posted.
Answer:
Assuming "x2" is x squared:
5x(x2-4x+2)
(5x(x2)+5x(-4x)+5x(2))
<u>5x^3-20x+10x</u>
For these polynomial multiplication problems, just distribute the number outside the parentheses.
Answer:
Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
Step-by-step explanation:
H0 : σ² = 2.66²
H1 : σ² < 2.66²
X²c = (n - 1)*s² ÷ σ²
sample size, n = 40
Sample standard deviation, s = 1.9
X²c = ((40 - 1) * 1.9²) ÷ 2.66²
X²c = 140.79 ÷ 7.0756
X²c = 19.897
Using a confidence level of 95%
Degree of freedom, df = n - 1 ; df = 40 - 1 = 39
The critical value using the chi distribution table is 25.6954
Comparing the test statistic with the critical value :
19.897 < 25.6954
Test statistic < Critical value ; Reject the Null
Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
