Answer:
24
Step-by-step explanation:

Negative and another negative makes a positive.

Add the fractions first.

5/5 is equivalent to 1. 7 5/5 becomes 8.

Add the numbers.

I hope this helps!
One third of 75 would be 25 because you divide 75÷3=25
Point A - 1
Point B - 5/6
Point C - 1/3
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you would add 3y+5y and get 8y=-20
then the slope would be 8/1 and your y-intercept would be -20
We are to find how long will it take to return to the ground?
Answer:
t = 0.48 sec
Step-by-step explanation:
We are given;
initial velocity; vi = 40 ft/s
hi = 70 ft
acceleration due to gravity; a = 32 ft/s²
Now, we are given that the rocket's height as a function of time is;
h = -12at² + vit + hi
At ground, h = 0
Plugging in the relevant values to obtain ;
0 = -12(32)t² + 40t + 70
-384t² + 40t + 70 = 0
The roots of the equation gives; t = 0.48 sec