The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
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Answer:
l = 24ft
Step-by-step explanation:
A = lw
360 = (x + 9)(x)
360 = x^2 + 9x
0 = x^2 + 9x - 360
0 = (x + 24)(x - 15)
x ≠ -24 (length cannot be negative)
x = 15
l = 15 + 9
l = 24ft
Answer:
123456678890
Step-by-step explanation:
I think this is the answer
Answer:
y = 2x
Step-by-step explanation:
Use Rise over Run. The rise(up/down) is 2 and the run(sideways) is 1. The slope is going up, not down so the 2 is positive. So, it is positive 2/1, which you can write as 2.