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leva [86]
2 years ago
6

The volume of a rectangular prism is given by the expression 2x^4+2x^3-4x^2-4x. Write the volume as the product its dimensions.

Remember, V = lwh.
Mathematics
1 answer:
telo118 [61]2 years ago
7 0
<h3>Answer:  2x(x^2-2)(x+1)</h3>

=========================================================

Explanation:

First factor out the GCF 2x

2x^4+2x^3-4x^2-4x

2x*x^3+2x*x^2-2x*2x-2x*2

2x(x^3 + x^2 - 2x - 2)

Then let's factor the expression inside the parenthesis using the factor by grouping method

x^3 + x^2 - 2x - 2

(x^3 + x^2) + (- 2x - 2)

x^2(x + 1) - 2(x + 1)

(x^2 - 2)(x+1)

We see that x^3 + x^2 - 2x - 2 factors to (x^2-2)(x+1)

Overall, the original expression fully factors to 2x(x^2-2)(x+1)

length = 2x

width = x^2-2

height = x+1

The order of length, width, and height doesn't matter.

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N = -1/10rt + 1/10q
= −14n+q+4n=rt−4n+4n
= −10n+q=rt
= −10n+q+−q=rt+−q
= −10n=rt−q
= -10n/-10 = rt-q/-10
So the answer is:
= n = -1/10rt + 1/10q
3 0
3 years ago
Read 2 more answers
what is the answer to this The sixth grade teachers ordered 54 bags of candy to be split among 12 students. How many bags of can
nadya68 [22]

Answer:

The answer is 4.5 and 9/2

Step-by-step explanation:

First

54 / 12 = 4.5

Then

Change it into a fraction

Write is fraction form 4.5 / 1

Multiply both numerator and denominator by 10 for every number after the decimal point

4.5 × 10

1 × 10

Which will equal 45/10

Then Reduce the fraction gives 9/2

3 0
3 years ago
Equivalent fraction for ½.
labwork [276]

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2/4

Step-by-step explanation:

half/whole for any number really

5 0
3 years ago
The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
jeyben [28]

Answer:

The period of Y increases by a factor of k^ {3/2} with respect to the period of X

Step-by-step explanation:

The equation T ^ 2 = a ^ 3 shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?  

For the planet Y:  

T_y ^ 2 = a_y ^ 3

For planet X:  

T_x ^ 2 = a_x ^ 3

To know the factor of aumeto we compared T_x with T_y

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:  

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So

\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x

Then, the period of Y increases by a factor of k^ {3/2} with respect to the period of X



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3 years ago
Which choices are equations for the line shown below? Check all that apply.
nata0808 [166]

Answer:

c and b

Step-by-step explanation:

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