N = -1/10rt + 1/10q
= −14n+q+4n=rt−4n+4n
= −10n+q=rt
= −10n+q+−q=rt+−q
= −10n=rt−q
= -10n/-10 = rt-q/-10
So the answer is:
= n = -1/10rt + 1/10q
Answer:
The answer is 4.5 and 9/2
Step-by-step explanation:
First
54 / 12 = 4.5
Then
Change it into a fraction
Write is fraction form 4.5 / 1
Multiply both numerator and denominator by 10 for every number after the decimal point
4.5 × 10
1 × 10
Which will equal 45/10
Then Reduce the fraction gives 9/2
Answer:
2/4
Step-by-step explanation:
half/whole for any number really
Answer:
The period of Y increases by a factor of
with respect to the period of X
Step-by-step explanation:
The equation
shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?
For the planet Y:
For planet X:
To know the factor of aumeto we compared
with
We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:
So
Then, the period of Y increases by a factor of
with respect to the period of X
Answer:
c and b
Step-by-step explanation: