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1 year ago

Find the equation of the line through point (8,−9) and perpendicular to 3+8=4.

1 answer:

4 0

The equation of the line through the point (8,−9) and perpendicular to 3x+8y=4 is given by 8x - 3y = 91.

We are aware that any straight line's equation can be expressed as

y = mx + c,

where m denotes the slope and c denotes a constant.

Also, two perpendicular lines' slopes are the negative reciprocals of one another.

Here, the equation of the given straight line is

3x+8y=4

i.e. 8y = 4 -3x

i.e. y = (4/8) - (3/8)x

Now the negative reciprocal of - 3/8 is 8/3.

Then we can write the equation of the perpendicular line is

y = (8/3)x + c ...(1)

Since (1) passes through the point (8, -9), so we can put x = 8 and y = -9 in (1) to get the value of c.

So, -9 = (8/3)*8 + c

i.e. -9 = 64/3 + c

i.e. c = -9 -64/3 = - (27 + 64)/3 = - 91/3

(1) can be written as

y = (8/3)x - (91/3)

i.e. 3y = 8x - 91

i.e. 8x - 3y = 91

Therefore the equation of the line through the point (8,−9) and perpendicular to 3x+8y=4 is given by 8x - 3y = 91.

Learn more about perpendicular lines here -

brainly.com/question/12209021

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3 years ago

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

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b) Addition

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d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0

2 years ago

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mash [69]

Answer:

10n -10

Step-by-step explanation:

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3 years ago

Read 2 more answers

Can someone pls help, I know this is kind of a lot but I’ve been stuck on this for a while now.

Greeley [361]

9514 1404 393

Answer:

(a, b, c) = (-0.425595, 11.7321, 2.16667)

f(x) = -0.425595x² +11.7321x +2.16667

f(1) ≈ 13.5

Step-by-step explanation:

A suitable tool makes short work of this. Most spreadsheets and graphing calculators will do quadratic regression. All you have to do is enter the data and make use of the appropriate built-in functions.

Desmos will do least-squares fitting of almost any function you want to use as a model. It tells you ...

a = -0.425595

b = 11.7321

c = 2.16667

f(x) = -0.425595x² +11.7321x +2.16667

and f(1) ≈ 13.5

_____

<em>Additional comment</em>

Note that a quadratic function doesn't model the data very well if you're trying to extrapolate to times outside the original domain.

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2 years ago