5/7+(-1/3)-(-1/2) Show work pls

7/x+2 + 3x-4/x2+5x+6=9

larisa [96]

Answer:

is this in graph or equation? ???

4 0

3 years ago

1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Read more about proportions at:

brainly.com/question/21126582

8 0

3 years ago

Solve system by elimination 8x-8y=-16 -8x-7y=-29

Gnesinka [82]

Add these together.
You get -15y=-45
So y=3

Now plug in to first equation.
8x-8(3)=-16
8x-24=-16
8x=8 so x=1

Check both values in second equation.
-8(1)-7(3)=
-8-21=-29

It works...so x=1, y=3

6 0

4 years ago

WILL GIVE BRAINLIEST A set of numbers is shown:

ad-work [718]

10 and 15 dear^^ 5(15) + 3(15) =28

4 0

2 years ago

L

yan [13]

Answer:

464.5cm³

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7 0

3 years ago